Difference between revisions of "Proc"
From Mesham
Jump to navigationJump to searchm (9 revisions imported) |
|||
| (7 intermediate revisions by the same user not shown) | |||
| Line 3: | Line 3: | ||
proc n<br> | proc n<br> | ||
{<br> | {<br> | ||
| − | + | process body<br> | |
} | } | ||
| Line 16: | Line 16: | ||
#include <io> | #include <io> | ||
| − | proc 0 { | + | function void main() { |
| − | + | proc 0 { | |
| − | + | print("Hello from 0\n"); | |
| − | + | }; | |
| − | + | ||
| − | + | proc 1 { | |
| + | print("hello from 1\n"); | ||
| + | }; | ||
}; | }; | ||
The code example will run on two processes, the first will display the message ''Hello from 0'', whilst the second will output the message ''hello from 1''. | The code example will run on two processes, the first will display the message ''Hello from 0'', whilst the second will output the message ''hello from 1''. | ||
| + | ''Since: Version 0.41b'' | ||
[[Category:Parallel]] | [[Category:Parallel]] | ||
Latest revision as of 15:44, 15 April 2019
Syntax
proc n
{
process body
}
where n is a variable or value known at compile time.
Semantics
This will limit execution of a block to a certain process whose rank is guaranteed to be that specified.
Note: A variable declared within a proc block and allocated multiple will in fact, by inference, be allocated to the group of processes which contains a single process who's rank is the same as the proc block's.
Example
#include <io>
function void main() {
proc 0 {
print("Hello from 0\n");
};
proc 1 {
print("hello from 1\n");
};
};
The code example will run on two processes, the first will display the message Hello from 0, whilst the second will output the message hello from 1.
Since: Version 0.41b
