Difference between revisions of "Reduce"
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== Semantics == | == Semantics == | ||
− | All processes in the group will combine their values together at the root process and then the operation will be performed on them. | + | All processes in the group will combine their values together at the root process and then the operation will be performed on them. |
+ | |||
+ | == Supported operations == | ||
+ | |||
+ | {{ Template:ReductionOperations }} | ||
== Example == | == Example == | ||
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var x:Int::allocated[multiple[]]; | var x:Int::allocated[multiple[]]; | ||
var p; | var p; | ||
− | par p from 0 to 3 | + | par p from 0 to 3 { |
− | |||
x:(x::reduce[1,"max"]; | x:(x::reduce[1,"max"]; | ||
x:=p; | x:=p; |
Revision as of 17:26, 12 January 2013
Syntax
reduce[root,operation]
Semantics
All processes in the group will combine their values together at the root process and then the operation will be performed on them.
Supported operations
Operator | Description |
---|---|
max | Identify the maximum value |
min | Identify the minimum value |
sum | Sum all the values together |
prod | Generate product of all values |
Example
var t:Int::allocated[multiple[]]; var x:Int::allocated[multiple[]]; var p; par p from 0 to 3 { x:(x::reduce[1,"max"]; x:=p; t:=x; };
In this example, x is to be reduced, with the root as process 1 and the operation will be to find the maximum number. In the first assignment x:=p all processes will combine their values of p and the maximum will be placed into process 1's x. In the second assignment t:=x processes will combine their values of x and the maximum will be placed into process 1's t.