Difference between revisions of "Reduce"

From Mesham
Jump to navigationJump to search
m
m
Line 19: Line 19:
  
 
In this example, ''x'' is to be reduced, with the root as process 1 and the operation will be to find the maximum number. In the first assignment ''x:=p'' all processes will combine their values of ''p'' and the maximum will be placed into process 1's ''x''. In the second assignment ''t:=x'' processes will combine their values of ''x'' and the maximum will be placed into process 1's ''t''.  
 
In this example, ''x'' is to be reduced, with the root as process 1 and the operation will be to find the maximum number. In the first assignment ''x:=p'' all processes will combine their values of ''p'' and the maximum will be placed into process 1's ''x''. In the second assignment ''t:=x'' processes will combine their values of ''x'' and the maximum will be placed into process 1's ''t''.  
 +
 +
''Since: Version 0.41b''
  
 
== Supported operations ==
 
== Supported operations ==

Revision as of 18:24, 13 January 2013

Syntax

reduce[root,operation]

Semantics

All processes in the group will combine their values together at the root process and then the operation will be performed on them.

Example

var t:Int::allocated[multiple[]];
var x:Int::allocated[multiple[]];
var p;
par p from 0 to 3 {
   x:(x::reduce[1,"max"];
   x:=p;
   t:=x;
};

In this example, x is to be reduced, with the root as process 1 and the operation will be to find the maximum number. In the first assignment x:=p all processes will combine their values of p and the maximum will be placed into process 1's x. In the second assignment t:=x processes will combine their values of x and the maximum will be placed into process 1's t.

Since: Version 0.41b

Supported operations

Operator Description
max Identify the maximum value
min Identify the minimum value
sum Sum all the values together
prod Generate product of all values